ABC is an isosceles right triangle in which AB has a slope of -1 and angle ABC = 90 degrees. Triangle ABC is dilated by a scale factor of 1.8 with the origin as the center of dilation, resulting in the image A'B'C'. What is the slope of B'C'?
@dumbcow
dilating only changes the length of the sides not the shape of the triangle you still have a isosceles right triangle with slope of -1 for A'B' so slope of B'C' is same as slope of original BC which is straight line or 0
Thank you @dumbcow I still don't understand it very well although you explained it but thank you for your time and knowledge :)
yw maybe a picture will help |dw:1416844926913:dw| sorry i misread the problem in this case BC is perpendicular to AB perpendicular slopes must always multiply to -1 ---> (-1)*x = -1 ----> x = 1 slope of BC = 1 thus B'C' is also 1
@AlondraAcosta
Oh okay I understand. Thank you so much @dumbcow
ok glad to help
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