Question

help pleasee

Answer 1

c^2 -4c +4/ 12^3 + 30c^2 (division sign) c^2 -4/ 6c^4 + 15c^3

Answer 2

A. c (c-2) / c (c+2)
b. 2 (c-2)/ c (c+2)
c. 2(c+2) / c(c-2)
d. c(C+2)/ 2(c-2)

Answer 3

is your expression this?
\[\frac{ c ^{2}-4c+\frac{ 4 }{ 12 }c ^{3}+30c ^{2} }{ c ^{2}-\frac{ 4 }{ 6 }c ^{4}+15c ^{3} }\]

Answer 4

no

Answer 5

if you could tell me ow to do the division line on the equation thing i can type it out

Answer 6

please can you rewrite your expression using the editor?

Answer 7

how do I make the line?

Answer 8

you have click on the tab which is at bottom on the right

Answer 9

\[c^2-4c+4/ 12c^3 + 30c^2 \div c^2 -4/ 6c^4+15c^3 \]

Answer 10

\[\frac{ c ^{2}-4c+\frac{ 4 }{ 12 }c ^{3} +30c ^{2}}{ c ^{2} }-\frac{ 4 }{ 6 }c ^{4}+15c ^{3}\]
is that?

Answer 11

no i will post a picture

Answer 12

Ok! I have
now I try!

Answer 13

ok

Answer 14

the firstratio can be rewritten as below:(1)
\[\frac{ (c-2)^{2} }{ 6c ^{2}(2c+5) }\]
whereas the secon ratio, namely the divisor, can be rewritten as below:(2)
\[\frac{ (c-2) }{ 3c ^{3}(2c+5) }\]
Now, we have to divide the expression (1) by the expression (2), i.e. we have to multiplicate the expression (1) by the inverse of expression (2), so we have:
\[\frac{ (c-2)^{2} }{ 6c ^{2}(2c+15) }*\frac{ 3c ^{3}(2c+5) }{ (c-2) }\]
after simplification, we can write:
\[\frac{ c(c-2) }{ 2 }\]

Answer 15

So would the answer be A?

Answer 16

oops I haqve made an error:
the secon expreession is:

Answer 17

\[\frac{ (c-2)(c+2) }{ 3c ^{3}(2c+5) }\]

Answer 18

so the final result is:
\[\frac{ c(c-2) }{ 2(c+2) }\]
so A.

Answer 19

@cookiimonster27 right answer is A.

Answer 20

@Michele_Laino could you help with a couple more?

Answer 21

Ok!

Answer 22

cool give me one sec to post it