Help with like 4 algebra 2 questions pleaseeee???
In order to combine, you have to have a common denominator, just like any fractional problem. In the first fraction, the denominator is missing the (x+5). In the second fraction, the denominator is missing the (x+2). To get the common denominator, you have to multiply the "missing piece" by both the top and bottom of the fraction. So, the first fraction, you would multiply by (x+5) top and bottom. Then do the same to the second fraction using (x+2). Now you should be able to combine like terms to simplify.
@becki ops i put the wrong one up again this is the right one
OK. So you need to get the x out of the denominator of the fraction in the denominator. :) If you multiply top and bottom by x through ALL the terms, that will remove the x. BUT you also need to get rid of the 8 in the denominator of the term in the numerator. So, let's multiply top and bottom by 8, also.
Multiply 8x by (1/8x) and by 3. Multiply 8x by 1 and by (2/x).
i got c is that right?
That's what I got. :) Good job.
could you help with this one also @Becki
Sure. The graph shows a vertical asymptote at 3. So, in which of the answers given can x NOT EQUAL 3? In other words, what value of x makes the denominator 0?
B AND D?
One is correct. :) If x=3 on answer B, your denominator is 0. You can't divide by zero or bad things happen. :) But if x=3 on answer D, your denominator is now 6, which is a perfectly good number to divide by. So....
D works
The correct answer is B. An asymptote occurs where x=3, because x=3 would cause black holes to form, penguins to die, and water to boil at 32 degrees.
Ohhh okay
Since the denominator can NEVER be 0, and x=3 would make that denominator 0; AND since you have an asymptote at x=3 meaning that the graph will never, ever, ever reach x=3, the answer is B.
awsome could you help with another?
Sure.
So the domain is the x value. Is there any number at all that we could put in for x that would make the denominator 0?
3
No. We could multiply 5 by 3^5 and not get 0.
oh
What multiplied by 5 equals 0?
0
Yes. So, the domain, or x-values, can be any number except 0. That leaves only 3 answers to choose from since answer B doesn't remove 0.
And because of that, any number we put in, except for 0, is going to yield a real number. That means the range is also any real number except for 0. f(x) can never equal 0 because there is no number we can put in for x that would cause it to equal 0.
great so its d
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