Question

How not to end up with [infinity/infinity]?
\[\lim_{x \rightarrow -\infty} \frac{ x-4 }{ x }\]

Answer 1

well......646463688987654357

Answer 2

Do you know L'hopital?

Answer 3

Is L'hopital dividing by the largest variable?

Answer 4

or something along the lines?

Answer 5

Or if you want, you can divide everything by x: \(\Large \frac{x-4}{x}*\frac{1/x}{1/x}\)

Answer 6

like so? \[\frac{ x/x - 4/x }{ x/x } = \frac{ 1-4/x }{ 1 }\]

Answer 7

No, L'hopital's rule is if you get a case like \(\frac{\infty}{\infty}\) or something you are allowed to take the derivative and find the limit again

Answer 8

and then the limit of 4/x is 0

Answer 9

Right, so you just end up with 1 ~

Answer 10

So the final answer would be 1?

Answer 11

Ah nice.

Answer 12

If you did L'hopital you would of gotten 1 too :P

Answer 13

If you ever wanna use/know about L'Hopital's: http://tutorial.math.lamar.edu/Classes/CalcI/LHospitalsRule.aspx

Answer 14

Good luck!

Answer 15

Will check it out, thanks for the help!