Question

HELP!!

Answer 1

please explain each step

Answer 2

can you please solve this with me step by step?

Answer 3

you're asked to integrate g'(x)

Answer 4

can you please solve this with me? ive listed this question so much because i dont understand it but nobody answers hahaa

Answer 5

can you factor the top?

Answer 6

(x+4)(x-4)

Answer 7

actually my bad, can you do long divison?

Answer 8

yes

Answer 9

ok then do it

Answer 10

wait im not sure

Answer 11

are you sure thats what im supposed to do ?

Answer 12

cause i get weird numbers

Answer 13

yes, to integrate this, you will have to do long division first

Answer 14

(x^-16)/(x-2) = x + 2 - 12/(x-2), now can you integrate

Answer 15

can you explain, im confused on this question..

Answer 16

you can not (x^2-16)/(x-2) directly. So you have to do long division.

since (x^-16)/(x-2) = x + 2 - 12/(x-2), the integral of (x^2-16)/(x-2) is the same as the integral of x+2 - (12/(x-2)

Answer 17

can not integrate*

Answer 18

integral of x = (1/2)x^2
integral of 2 = 2x
integral of 12/(x-2) = 12ln|x-2|

so (1/2)x^2 + 2x - 12|ln-2| + C

Answer 19

ok got it so far

Answer 20

(1/2)x^2 + 2x - 12ln|x-2| + C

Answer 21

so g(x) =(1/2)x^2 + 2x - 12ln|x-2| + C

you're given g(3) = 4. I.e (x,y) = (3,4). Plug the point in to solve for C.

Answer 22

-144? @sourwing

Answer 23

https://www.wolframalpha.com/input/?i=y+%3D+%281%2F2%29x%5E2+%2B+2x+-+12ln%7Cx-2%7C+%2B+C%2C+x%3D3%2Cy%3D4

Answer 24

thank you !