Example 3. In a truck-loading station at a post office, a small 0.200-kg package is released from rest at point A on a track that is one-quarter of a circle with radius 1.60 m, as shown below. It slides down the track and reaches point B with a speed of 4.80 m/s. From point B, it slides on a level surface a distance of 3.00 m to point C, where it comes to rest. Determine (a) the acceleration of the package; (b) the kinetic coefficient of friction between the package and the horizontal surface; (c) friction and the normal force.

Question

anonymous · Answer

Here is a picture

anonymous · Answer

Brother, how do you make an attachment? I thought you had to go the left hand side of 'post', but nothing.

anonymous · Answer

Anyway, let us go for step a)
Given that v^2=u^2+2as, make a subject of the formula.

anonymous · Answer

Where the v is 4.8, u is 0, s is 1.6.

anonymous · Answer

C) again, use the formula I gave you for b, where v is 0, u is 4.8, s is 3 and find a.
Secondly, use the formula -Ff=ma , where Ff is frictional force. And your m is the 0.2kg.. Since there arr no any vertical forces but the weight of the truck, then R is definetely equal to the weight of the truck, which is 0.2*9.81.
B) let the coefficient of friction be 'mu'.
Use the formula Ff=muR. Replace with the values you found inc) and simply find mu.