A particle moves on a straight line away from its initial position so that after t seconds its position is given by s = 2T(squared) + 3T in feet from its initial position. a. Find the average velocity of the particle between 2 and 5 seconds. b. Use the derivative to find the instantaneous velocity of the particle at T=1 second and T=8 seconds.
average velocity on [a,b] is [s(b) - s(a)] / ( b - a)
so you can plug in t = 2 and t = 5 for 'a' and 'b'
Why is it that? I mean, why do you get s(b)-s(a)/(b-a) ?
My math teacher said something about a timeline. Is there a way to use a timeline for this?
IDK what you mean by timeline here but the average of anything is the f(x2)-f(x1)/x2-x1 or the slope in other ways between two points one is final position and one is initial position
the second part you need to take the derivative with respect to time and then evaluate at t=1 and at t=8
Average velocity is given by the total change in position divided by the total change in time.
Join our real-time social learning platform and learn together with your friends!