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Find the equation of the line with a slope of -1 that is the tangent to the curve y=1/(x-1)
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have you found y'
I can't use derivatives yet.
that is weird this question requires derivatives
what ways are you suppose to use if you haven't had derivatives mentioned
are you there?
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I can try to help you figure it out if you tell me what you guys have been doing to find slopes of curves or a point associated with a given slope for a curve.
but the only way I can think of is using derivatives so far \[f'(x)=\lim_{h \rightarrow 0}\frac{f(x+h)-f(x)}{h}\]
The curve is a two part curve. There is a positive curve and a negative curve. And an asymptote at x = 1
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