Question

Which equation is graphed here?

http://static.k12.com/calms_media/media/1312500_1313000/1312639/1/5634cf4cc78c5f954e9151076931e1346ad3a658/HS_A1G2_S1_07_08_ART1.jpg

A.y-3=-2/3(x+1)


B.y-4=-3/2(x+2)


C.y-1=-3/2(x+3)


D.y+1=-2/3(x-3)

Answer 1

pick 2 points off the graph
say 0,1 and 2, -2

and get the equation \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 0}}\quad ,&{\color{blue}{ 1}})\quad &({\color{red}{ 2}}\quad ,&{\color{blue}{ -2}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 2

Huh? @jdoe0001

Answer 3

@twvogels i think it's B am i correct

Answer 4

what did you get for the slope?

Answer 5

-3/2

Answer 6

well... then just plug in the values along with that slope, and that's the function :)

Answer 7

So i was right?

Answer 8

hmmm

Answer 9

I take it that's a no?

Answer 10

well... your slope is correct....
lemme recheck

Answer 11

yes... if we pick instead say another point
-2, 4 and use the slope of -3/2

is B \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -2}}\quad ,&{\color{blue}{ 4}})\quad &({\color{red}{ 2}}\quad ,&{\color{blue}{ -2}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies -\cfrac{3}{2}
\\ \quad \\

y-{\color{blue}{ 4}}={\color{green}{ -\cfrac{3}{2}}} (x-{\color{red}{(-2)}})\implies y-4=-\cfrac{3}{2}(x+2)\)