Geometry help? Will fan and medal!!
sup
what is the question?
^^
Realize that since ABC is an equilateral triangle, all angles, A, B, and C are 60 degrees each.
Realize that Triangle BCD is a 30-60-90 right triangle, becuase in an equilateral triangle, the height, BD, is perpendicular to side AC, so angle D is 90 degrees.
We want the length of BD. BD is the side opposite the 60-degree angle, angle C. As we said before, angle C is 60 degrees.
Okay. I see that
In a 30-60-90 right triangle, the side opposite the 60-degree angle is 1/2 the hypotenuse multiplied by sqrt(3). Therefore, BD = (1/2)of 8 multiplied by sqrt(3) = 4 sqrt (3)
does that make sense?
yeh
your welcome
You can also do this with the Pythagorean theorem. Since triangle ABC is equilateral, and all its sides measure 8, then segment CD measures 4. Triangle BCD is a right triangle with a hypotenuse of length 8 and a leg of length 4. You can use the Pythagorean theorem to find the length of the other leg, segment BD. \(a^2 + b^2 = c^2\) \(4^2 + (BD)^2 = 8^2\) \(16 + (BD)^2 = 64\) \((BD)^2 = 48\) \(BD = \sqrt{48} = \sqrt{16 \cdot 3}\)\) \(BD = 4\sqrt{3} \)
@sammixboo i posted it
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