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OpenStudy (anonymous):
Evaluate the limits
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OpenStudy (anonymous):
OpenStudy (freckles):
so you know that |x|=x if x>0 and |x|=-x if x<0 correct?
OpenStudy (freckles):
except the highest degree inside the square root is 4
and the highest degree on bottom is 2
so we are dividing both top by sqrt(x^4)
OpenStudy (freckles):
\[\sqrt{x^4}=x^2 \text{ for all x so we don't have to worry about the }\\ \text{ splitting of cases like with } \sqrt{x^2}=|x|\]
OpenStudy (freckles):
you got it from here?
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OpenStudy (anonymous):
wait so we have to divide both the numerator and the denominator by x^4?
OpenStudy (jhannybean):
Dividing it by \(\sqrt{x^4} = x^2\)
OpenStudy (jhannybean):
Follow @freckles explanation.
OpenStudy (anonymous):
so how would i rewrite if after i divide by that?
OpenStudy (freckles):
\[\frac{\frac{\sqrt{x^4-8x^3+9}}{\sqrt{x^4}}}{\frac{5x^2-9}{\sqrt{x^4}}}\]
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OpenStudy (freckles):
we divided both top and bottom by x^2 because we had the deg of the bottom was 2
OpenStudy (freckles):
we rewrote x^2 as sqrt(x^4) mainly because of the top
OpenStudy (freckles):
sqrt(x^4) though is equal to x^2 for all x
OpenStudy (freckles):
\[\frac{\sqrt{\frac{x^4-8x^3+9}{x^4}}}{\frac{5x^2-9}{x^2}}\]
OpenStudy (freckles):
can you play with this?
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OpenStudy (anonymous):
and then we can cancel the x^2 next to the 5 right? so the bottom would be? |dw:1416882346436:dw|
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