Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Evaluate the limits

OpenStudy (anonymous):

OpenStudy (freckles):

so you know that |x|=x if x>0 and |x|=-x if x<0 correct?

OpenStudy (freckles):

except the highest degree inside the square root is 4 and the highest degree on bottom is 2 so we are dividing both top by sqrt(x^4)

OpenStudy (freckles):

\[\sqrt{x^4}=x^2 \text{ for all x so we don't have to worry about the }\\ \text{ splitting of cases like with } \sqrt{x^2}=|x|\]

OpenStudy (freckles):

you got it from here?

OpenStudy (anonymous):

wait so we have to divide both the numerator and the denominator by x^4?

OpenStudy (jhannybean):

Dividing it by \(\sqrt{x^4} = x^2\)

OpenStudy (jhannybean):

Follow @freckles explanation.

OpenStudy (anonymous):

so how would i rewrite if after i divide by that?

OpenStudy (freckles):

\[\frac{\frac{\sqrt{x^4-8x^3+9}}{\sqrt{x^4}}}{\frac{5x^2-9}{\sqrt{x^4}}}\]

OpenStudy (freckles):

we divided both top and bottom by x^2 because we had the deg of the bottom was 2

OpenStudy (freckles):

we rewrote x^2 as sqrt(x^4) mainly because of the top

OpenStudy (freckles):

sqrt(x^4) though is equal to x^2 for all x

OpenStudy (freckles):

\[\frac{\sqrt{\frac{x^4-8x^3+9}{x^4}}}{\frac{5x^2-9}{x^2}}\]

OpenStudy (freckles):

can you play with this?

OpenStudy (anonymous):

and then we can cancel the x^2 next to the 5 right? so the bottom would be? |dw:1416882346436:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!