Question

!! Help please? :3
How do I find the axis of symmetry, for each of these 3 functions?

Answer 1

Umm, I'm sorry, but it's rude to post a question on my question :/

Answer 2

the third one you do with your eyeballs

Answer 3

Right. I believe the third one is x=-2?

Answer 4

the second one you do by finding \(-\frac{b}{2a}\)

Answer 5

yeah looks like \(x=-2\) to me

Answer 6

Nice =w= xD

Answer 7

you got the second one?

Answer 8

^ I think that's right xD Not sure

Answer 9

@satellite73, So for the second one, in short, x = 1?

Answer 10

yes, \(x=1\) is right

Answer 11

Got it! XD And lastly, how about for the first one? ^^

Answer 12

it is already in vertex form \(y=a(x-h)^2+k\) has axis of symmetry \(x=h\)

Answer 13

x=h? As in, x = 4? :o

Answer 14

@satellite73

Answer 15

>x=h? As in, x = 4? Yes, that is correct for the first problem, y = -2(x-4)^2 + 2

@Xaze

Answer 16

@Directrix, Why, thank you! :3