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!! Help please? :3 How do I find the axis of symmetry, for each of these 3 functions?
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Umm, I'm sorry, but it's rude to post a question on my question :/
the third one you do with your eyeballs
Right. I believe the third one is x=-2?
the second one you do by finding \(-\frac{b}{2a}\)
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yeah looks like \(x=-2\) to me
Nice =w= xD
you got the second one?
^ I think that's right xD Not sure
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@satellite73, So for the second one, in short, x = 1?
yes, \(x=1\) is right
Got it! XD And lastly, how about for the first one? ^^
it is already in vertex form \(y=a(x-h)^2+k\) has axis of symmetry \(x=h\)
x=h? As in, x = 4? :o
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@satellite73
>x=h? As in, x = 4? Yes, that is correct for the first problem, y = -2(x-4)^2 + 2 @Xaze
@Directrix, Why, thank you! :3
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