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Chemistry 8 Online
OpenStudy (anonymous):

9.90 g of NH4Cl is added to 19.0 g of water. Calculate the molality of the solution.

OpenStudy (anonymous):

\[m = \frac{ (mole) of solute }{ (Kg) of solvent }\]

OpenStudy (anonymous):

you should convert gram to Kg

OpenStudy (anonymous):

and find mole using... \[mole = \frac{ mass }{ molarmass }\]

OpenStudy (anonymous):

9.90 g of NH4Cl > is solute water is soluton

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