Question

I need some help with algebra 2 please!!!

Answer 1

@absurdism

Answer 2

sure, post your equations

Answer 3

x+y equals 3

Answer 4

y-0 equals 1(x+3)

Answer 5

y equals 2x+(-4)

Answer 6

the DOMAIN set describes what numbers CAN go into the function without giving you an erroneous expression (a bad expression, like division by 0)
the RANGE set describes what numbers are made as a RESULT of the domain inputs.

Answer 7

and y equals -1x+3

Answer 8

x + y = 3
rearrange this into slope-intercept form
y = -x + 3
are there any numbers we can or cannot put into this? are there any numbers that we can't make with this function?

Answer 9

i understand that but im not really sure what to do? like i have no idea what those definitons mean, like my mind cant grasp the concept

Answer 10

@skatergurl916

Answer 11

Um, i dont think we can put anything into it?

Answer 12

@Jhannybean

Answer 13

like, by "put in" i mean substitute x for a number

Answer 14

no

Answer 15

maybe 1?

Answer 16

i dont get this very well but theres a site that will give u all the answers u need

Answer 17

how so? you can put any number into this function and it'll be fine, look
y = -0 + 3
y = -1 + 3
y = -99999 + 3
it's all fine

Answer 18

but doesnt that change the slope?

Answer 19

Graph your equation, maybe that will help.

Answer 20

oh so does that mean i can put any number for the slope because of the domain?

Answer 21

The domain is all the x values from negative infinity to positive infinity, so is there any place where the domain would not exist for this line?

Answer 22

i dont understand the question on my assignment.. would any restriction apply to the domain and range in the equations i created

Answer 23

Similar for range, range is all the y values across the y-axis. Is there any place where the y values would be discontinuous?

No, for both of these cases.

Answer 24

ohh, so there are endless possiblies for this equation?

Answer 25

Yes.

Answer 26

okay so i should write something like... when changed to slope intercept form .. the domain and range are endless?

Answer 27

what about y-0 equals 1(x+3) would the possiblies be endless there as well.. sorry im a little confused.

Answer 28

the domain and range range from \((-\infty \ , +\infty)\)

Answer 29

y-0 = 1(x+3)

y = x + 3

It's the same thing, your first equation is in slope-intercept form and this equation is in point-slope form.

Answer 30

so for all of my equations the domain and range would have no restrictions?

Answer 31

Nope.

Answer 32

oh.. how do i know when there is a restriction?

Answer 33

When there is either a removable discontinuity, (your function y is in some kind of fraction form where you have to solve for the denominator and the numerator)

In these cases you'll be finding vertical and horizontal asymptotes from my knowledge of it, or from what I can remember.

Answer 34

Lol... can you rephrase that in baby words please?

Answer 35

im sorry i really dont understand

Answer 36

Ok, like... if your function was \[y=\sqrt{x}\] Your restriction for the domain would be \(x \ge 0\)

Answer 37

That is a restriction because it "restricts" your domain to being only real numbers ranging from 0 to +ve infinity.

Answer 38

so anything in the negitives would be wrong..?

Answer 39

It wouldn't be wrong, you would get imaginary values, domain restrictions with i's and stuff.

Answer 40

okay.. thank you soooo much for you help but i honestly dont think im ever going to understand this. i cant grasp it.

Answer 41

Try this. http://www.sparknotes.com/math/algebra2/functions/section2.rhtml