Question

...

Answer 1

to represent a plane, you need `normal vector` and a `point`

Answer 2

cross the direction vectors of given lines for `normal vector`

Answer 3

yes cross product gives you the normal

Answer 4

are you dont with question 1 ?

Answer 5

*done

Answer 6

looks good!

Answer 7

two vectors are perpendicular iff the dot product is 0

Answer 8

direction vector of first line : <k, 2, k-1>
direction vector of second line : <-2, -1, 1>

Answer 9

take their dot product, set it equal to 0 and solve k

Answer 10

change the given lines to parametric form

Answer 11

x-1/k = y-2/2 = z+1/k-1

and

x+3/-2 = z/1, y=-1

Answer 12

\[\large \rm \dfrac{x-1}{\color{red}{k}} = \dfrac{y-2}{\color{Red}{2}} = \dfrac{z+1}{\color{red}{k-1}}\]

Answer 13

in symmetric form of line, the bottom stuff givs u the direction vector

Answer 14

k=3 is correct!

Answer 15

np:)