What is the diameter of the following circle: (x + 4)2 + (y – 9)2 = 18
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OpenStudy (anonymous):
diameter =2r
OpenStudy (mathstudent55):
Circle \((x - h)^2 + (y - k)^2 = r^2\) has radius r and diameter 2r.
OpenStudy (anonymous):
so times 18 by 2?
OpenStudy (mathstudent55):
No.
18 is r^2.
First find r. Then multiply it by 2.
OpenStudy (anonymous):
im confused
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OpenStudy (freckles):
is is another word for equal
r^2=18 <--can you solve this for r so that you have the radius
OpenStudy (anonymous):
so r is 9 ?
OpenStudy (freckles):
hmm 9^2=9(9) isn't 18
OpenStudy (mathstudent55):
I'll give you an example:
In the circle \((x - 4)^2 + (y - 3)^2 = 9\),
the center is (4, 3), and the radius is 3, since 3^2 = 9.
You take the square root of 9 and get 3. That is the radius.
OpenStudy (mathstudent55):
In your case. r^2 = 18
Take the square root of 18 to find the radius.
Then multiply the radius by 2 to find the diameter.
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OpenStudy (anonymous):
so it'll be 8.48?
OpenStudy (mathstudent55):
You probably need an exact answer.
This is how you do it.
\(r = \sqrt{18}\)
\(d = 2\sqrt{18} = 2 \sqrt{9 \cdot 2} = 2 \sqrt{9}\sqrt{2} = 2 \cdot 3\sqrt{2} = 6\sqrt2\)