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Mathematics 50 Online
OpenStudy (anonymous):

A confusing math logarithm problem.

OpenStudy (anonymous):

\[x^3-x=\log(x+1)\]please guide, don't do it for me, tho...

OpenStudy (anonymous):

@tkhunny can you please help?

OpenStudy (tkhunny):

What do you want to do with it? There is no simple, algebraic, closed-form expression for the solution. How are your numerical methods?

OpenStudy (anonymous):

Well, I saw this in my book, and I have to solve for x.

OpenStudy (anonymous):

I can guess that zero is a solution, because 0^3 - 0 = log(1) since log(1) is zero.

OpenStudy (tkhunny):

No, you don't. It can't be done. Some author is pulling your leg.

OpenStudy (tkhunny):

Guessing is certainly a valid method, particularly since nothing else will produce anything.

OpenStudy (anonymous):

So, there is NO WAY to "solve" it?

OpenStudy (anonymous):

I plugged it into wolfram and it gave me a second solution, approximately 1.28 or something like this.

OpenStudy (anonymous):

Well, if not, not... thank you for the help:)

OpenStudy (tkhunny):

No, there are many ways to solve it. 1) Guessing. 2) Various numerical methods. If it is a Base 10 logarithm, the second solution is between 1.13 and 1.14. If it is a Base e logarithm, the second solution is between 1.28 and 1.29. Please specify the base of logarithm functions when it is not ultimately obvious.

OpenStudy (tkhunny):

For example, after six applications of "Newton's Method", starting with x = 1, we achieve 1.28201560047703.

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