Question

The whole thing is a fraction.
K
N^t =--------------
[K-N^3]
1+[------]e^-rt
[ N^3 ]
Solve for N
...yep.

Answer 1

\[N^t=\frac{K}{1+\frac{K-N^3}{N^3}e^{-rt}}\]?

Answer 2

That's what is is.

Answer 3

well hmm.. I don't know if we can solve it for N
but we can try
-
I would first get rid of that compound fraction

Answer 4

have you done that?

Answer 5

or know how?

Answer 6

Class: 2+2
Homework: 145*3421
Quiz: 232/121*362^3

Answer 7

I have no idea how to do ANY of this stuff.

Answer 8

I'm sorry that does that mean

Answer 9

what does that mean*

Answer 10

2+2=4...

Answer 11

It means that either we never went over this stuff, or I wasn't paying attention.

Answer 12

i don't know what class homwork, quiz has to do with this problem

Answer 13

Just...never mind. What I'm saying that in class it's easy, homework...meh, quiz=WHAT THE HECK IS THIS

Answer 14

oh I thought you were trying to give me additional stuff to the problem

Answer 15

Oh.

Answer 16

\[N^t=\frac{K}{1+\frac{K-N^3}{N^3e^{rt}}} \cdot \frac{N^3e^{rt}}{N^3e^{rt}} \]
I'm going to multiply top and bottom by N^3e^{rt} so I can get rid of the compound fraction
tell me what we have as a result

Answer 17

It's multiple choice, if that helps at all.

Answer 18

A. N^1 +e^-rt KN^t-3 -e^-rt N^1 =K




B. N^1 +K^-rt KN^t-4 -e^-rt N^1 =K




C. N^1 +e^-rt KN^t-3 -e^-rt K^1 =N




D. K^4 +e^-rt KK^t-3 -e^-rt N^1 =K

Answer 19

Does it help?

Answer 20

@myininaya

Answer 21

It is weird the directions say to solve for N when that isn't what happened

Answer 22

Like there is still N on both sides of the equation on C

Answer 23

Can you post a picture of the question?

Answer 24

I want to see the exact wording.

Answer 25

and see if the actual equation is right

Answer 26

unless @mathstudent55 can use his esp skills to figure out what we are suppose to do :p

Answer 27

I wonder why they wrote N^1 instead of N
or K^1 instead of K

Answer 28

Like I said I think I need to see a picture of this question