Question

MEDAL AND FAN!!
A country's population in 1991 was 48 million. In 2002 it was 51 million. estimate the population in 2008 using the exponential growth formula. Round to nearest million.

Answer 1

so we will model it with exponential growth :
Ae^(bt)
t - years
now lets start counting from 1991 so that 1991 means t=0
so:
A = 48 million.
now in order to find b we will use the fact that in 2002 (t=11) the the population was 51 million:
48e^(11b) = 51

can you find b?

Answer 2

0.0055?

Answer 3

yes!
so your function is
48e^(0.0055t)
now you can find the value in 2008

Answer 4

how do I find value in 2008?

Answer 5

you should plug the correct value for t

Answer 6

so what would i plug in?

Answer 7

we said that 1991 corresponds to t=0
so 2008 means t = 17

Answer 8

I don't know how to do that :/

Answer 9

this class is almost over too

Answer 10

48e^(0.0055 * 17)

Answer 11

52.70?

Answer 12

5270

Answer 13

52.7 million ..
so 53 million

Answer 14

(rounded)