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Chemistry 15 Online
OpenStudy (anonymous):

Samuel the chemistry student prepares lead(ii) iodide from 1.55 g of lead(i) nitrate and potassium iodide. If Samuel collected 2.01 g of Pbl2, and the theoretical yield is 11.6 g, what is the percent yield?

OpenStudy (anonymous):

@JFraser

OpenStudy (anonymous):

@perl

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

@robtobey

OpenStudy (australopithecus):

Percent Yield = (Experimental Yield/Theoretical Yield)*100

OpenStudy (anonymous):

but whats the experimental yield

OpenStudy (jfraser):

"if samuel collected 2.01g"

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