Question

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Answer 1

@campbell_st

Answer 2

for this type of question I always use the general form

\[(x - h)^2 = 4a(y - k)\]

the vertex is (h, k) and the focal length is a

so start by finding the focal length...

the distance between the directrx and focus on the line of symmetry is souble the focal length

so how far between y = -2 and y = 6...?

Answer 3

4?

Answer 4

No 8

Answer 5

My bad, I did it wrong

Answer 6

can you just check the directrixx is y = -2 and focus is (2, 6)

Answer 7

great, 8 is correct...

so to find the value of a, just ahlve the answer you has for the distance between the focus and directrix...

Answer 8

thedirectrix is below the focus... so the parabola is concave up...

and the vertex is a units below the focus on the line of symmetry x = 2

so the vertex is (2, 6 - a)

Answer 9

Kinda confused, do I need to subtract something?

Answer 10

ok... you need to find a, based on the information

2a = 8 the disatnce between y = -2 and y = 6

so what is the value of a..?

Answer 11

4

Answer 12

great

the vertexx of the parabola is a units below the focus on the line x = 2

so the vertex is (2, 6 - a)

using your value of a, what is the vertex..?

Answer 13

If I draw a simple plot of the info I know the parbola is concave up