Question

I just want to be sure if this is correct ( this is trig math if you're not in it or taken it don't answer it)

Answer 1

would this be the Sum-Difference Formula?

Answer 2

hints:

sin^2 + cos^2 = 1

-(sin^2 + cos^2) = -1

and

csc = 1/sin

Answer 3

my teacher didn't go over the identities with us except for the Pythagorean Identities

Answer 4

so sin^2 + cos^2 = 1 looks familiar right?

Answer 5

ohhhh haha so my equation is a Pythagorean Identity?

Answer 6

also, does \[\Large \csc(\theta) = \frac{1}{\sin(\theta)}\] look familiar?

Answer 7

that's the Reciprocal identity

Answer 8

yes

Answer 9

so use that idea to get
\[\Large \sin(\theta)\csc(\theta) - \sin^2(\theta) = \cos^2(\theta)\]
\[\Large \sin(\theta)*\frac{1}{\sin(\theta)} - \sin^2(\theta) = \cos^2(\theta)\]
what's next?

Answer 10

\[1/\sin(\theta)\sin(\theta)\]

on the right side?

Answer 11

when it comes to proving identities, you only work on one side and leave the other side alone

Answer 12

it's easier to start with a more complicated side and simplify it down

so that's why I'm starting on the left side

Answer 13

would you do something about that \[\sin^2\]

Answer 14

what happens with the sin times 1/sin

Answer 15

ohhhhhh this might take a bit but I think I got it

Answer 16

nvm that's all I got