Question

Solve \[2e^{x}(e^{x}-e)=3e^{x}-4\]

Answer 1

\[2e^{x}(e^{x}-3)=3e^{x}-4\]

Answer 2

distribute on the left hand side first

Answer 3

then put everything on one side
you should see a quadratic in terms of e^x

Answer 4

i really dont get this at all, like i got nothing :(

Answer 5

Awesome. Thanks!

Answer 6

for what?

Answer 7

Let me know if you need further help @Dscdago

Answer 8

help mee pleasee

Answer 9

Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length.
A two-column proof of the theorem is shown, but the statement and reasons are not in correct order.

A triangle with vertices A is at 6, 8. B is at 2, 2. C is at 8, 4. Segment DE with point D on side AB and point E is on side BC


Statement Reason
I The coordinates of point D are (4, 5) and coordinates of point E are (5, 3) By the midpoint formula
II Segment DE is half the length of segment AC. By substitution
III Length of segment DE is Square root of 5 and length of segment AC is 2 multiplied by the square root of 5 By the distance formula
IV Segment DE is parallel to segment AC. Slopes of parallel lines are equal.
V Slope of segment DE is -2 and slope of segment AC is -2. By the slope formula

Which is the most logical order of statements and reasons for the proof?
II, III, I, IV, V
I, III, II, V, IV
I, III, II, IV, V
III, II, I, V, IV

Answer 10

@freckles

Answer 11

@
dan815

Answer 12

@dan815

Answer 13

@freckles how does the quadratic look like? to make sure

Answer 14

\[2e^x(e^x-3)=3e^x-4 \\ 2e^{2x}-6e^x=3e^x-4 \\ 2e^{2x}-6e^{x}-3e^{x}+4=0 \\ 2e^{2x}-9e^{x}+4=0\]

Answer 15

where e^x=u

Answer 16

Got it now. Thanks again!