Maximize profit given constraints
Here's what I did: \[P(n) = (100-n)(720+10n-80)\] \[P(n) = 72,000 + 1000n - 8000 - 720n - 10n^{2}\] \[P(n) = 64,000 + 280n - 10n^{2}\] \[P \prime (n) = 280 - 20n = 0\] \[280 = 20n\] \[n = 14\] How do I use the n = 14 to find monthly rent?
@ganeshie8 Do you know how to do this?
rent = 720 + 10n right ?
yes
it wouldn't take $860 though
looks there is a mistake in 2nd line
you should get 6 terms when you multiply a binomial and a trinomial but you have only 5 terms in 2nd line... check once
yeah you're right. I actually had the 80n on paper but forgot to consider it on paper, and then I just totally omitted it on here >_> thanks. The answer is (720 + 10n), n = 18 so (720 + 10(18)) = $900 monthly rent
looks good!
Join our real-time social learning platform and learn together with your friends!