Shortest distance between curve and point?
\[y=\frac{ 7 }{ x } , \left( 0, 0 \right)\]
|dw:1416969133351:dw| Would I use Pythagorean thm? \[c ^{2} = x ^{2} + \left( \frac{ 7 }{ x } \right)^{2}\]
shortest line between a point and a curve is perpendicular to the tangent line of the curve find slope of tangent using derivative \[\frac{dy}{dx} = -\frac{7}{x^2}\] thus slope of perpendicular line is: \[m = \frac{x^2}{7}\] Now slope of line between origin and any point on curve is: \[\frac{y}{x} = \frac{\frac{7}{x}}{x} = \frac{7}{x^2}\] Set these slopes equal to each other and solve for x: \[\rightarrow \frac{x^2}{7} = \frac{7}{x^2}\] \[x = \sqrt{7}\] thus point on curve closest to origin is: \[(\sqrt{7}, \sqrt{7})\]
oh yes you can also use pythagorean thm to obtain distance function you then would have to minimize distance by setting derivative equal to 0
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