Find the f^-1(y) inverse of F(x) F(x)=x-10
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
so f^-1(x) =x+10
Yup lol
Oh hold on you're finding f^-1(y)
i dont get it?....
So since you're solving for f^-1(y) it's even easier, you're just solving for x, let f(x) = y, so y = x-10 and solve for x.
so whats the answer.
y = x-10 solve for x and then let x = f^-2(y)
f^-1(y)*
your getting me confused you tell me to slove for x so its gonna be x=y-10 all over again.
F(x)=x-10 y=x-10 x=y-10 y=x-10 correct? or wrong final answer F^-1= 10 +x or why i dont know
Your question is asking for f^-1(y) I gave you steps to solve for f^-1(x), but I told you it's even easier if you need to solve for f^-1(y) since you're given f(x). I think you don't know what inverse means.
\[f^{-1}(y) \] this means you need a y variable in your final answer. You're given \[f(x) = x-10 \implies y = x-10\] now just solve for x. \[x = y+10 \implies f^{-1}(y) = y+10\] because it's a function of y we have to have a y variable or it wouldn't make sense.
ok i get it
So you have the function f(x) which we can say is going towards the right -> and the inverse of f(x) which is f^-1(x) means we go the opposite direction so towards the left <-, that's why we can cancel things out using the inverse.
Yeah, it's sort of messy when you first learn it haha.
what about F(x)=x/6 +3
Are you solving for f^-1(x) or f^-1(y)?
f^-1(y)
So do the same steps as the last question, let f(x) = y and solve for x then let x = f^-1(y).
F(x)=x/6 +3 y=x/6 +3 y-3= x/6 7-3/6=x so F^-1(y)= y-3/6
Why are you dividing by 6?
To get rid of the 6 on the right side you need to multiply both sides by 6 :p
oh yeah my mistake so F^-1(y)=6(y-3)
There we go :)
F(x)=3x+7 F^-1(y)=y-7/3 correct?
Yes, you're dividing by 3 for the whole expression right? f^-1(y) = (y-7)/3
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