Question

Given that f(x) =x^8h(x) h(-1) = 2 and h (-1) = 5 calculate f (-1)?

Answer 1

so given that \[f(x) = x^8h(x), h(-1) =2, h(-1) =5 \] what is \[f'(-1)\]

Answer 2

I'm assuming one of those h(-1) is h ' (-1)

Answer 3

yes sorry

Answer 4

which one

Answer 5

the second one is \[h'(-1) = 5\]

Answer 6

you first use the product rule, then you plug in x = -1

\[\Large f(x) = x^8*h(x)\]

\[\Large f'(x) = 8x^7*h(x) + x^8*h'(x)\]

\[\Large f'(-1) = 8(-1)^7*h(-1) + (-1)^8*h'(-1)\]

\[\Large f'(-1) = ???\]

Answer 7

-11?

Answer 8

getting the same