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At noon, ship A is 10 nautical miles due west of ship B. Ship A is sailing west at 18 knots and ship B is sailing north at 18 knots. How fast (in knots) is the distance between the ships changing at 7 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)
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let t hours be some time past 12:00 noon After t hours, ship B has gone 20t knots and ship A has gone 17t knots let the distance between them be D I see a right-angled triangle and D^2 = (20t)^2 + (17t+10)^2 D^2 = 689t^2 + 340t + 100 2D(dD/dt) = 1378t + 340 dD/dt = (689t + 170)/D at 4:00 pm, t=4 and D^2 = 12484 D = 111.7318 so at t=4 dD/dt = (689(4) + 170)/111.7318 = 26.19 knots
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