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Mathematics 20 Online
OpenStudy (anonymous):

Wait what? (Picture attached)

OpenStudy (anonymous):

OpenStudy (anonymous):

hmmm it is really hard wow

OpenStudy (campbell_st):

let the denominator be g(x) then replace denominator with x and call it f(x) then if you substitute g(x) into f(x) you get the solution shown

OpenStudy (anonymous):

So f(x) is|dw:1417050118181:dw|

OpenStudy (anonymous):

and g(x) is x^2

OpenStudy (campbell_st):

that makes a lot of sense

OpenStudy (anonymous):

Im asking you..

OpenStudy (campbell_st):

well as I can't give answers... does it make sense to you..?

OpenStudy (anonymous):

No. Why cant f(x) be x and g(x) be (2/(x^2))+3

OpenStudy (campbell_st):

that works as well

OpenStudy (anonymous):

It can be more than one thing?

OpenStudy (campbell_st):

yes...you can decide f(x) = x + 3 g(x) = 2/x^2 thats another

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