The inverse of 5x+6 is (x-6)/5 right?
No - the inverse of 8 is 1/8
\[\text{ does } \frac{(5x+6)-6}{5} \text{ give you } x? \\ \text{ or } \\ 5(\frac{x-6}{5})+6 \text{ give you x}\]
So im guessing im not right
I'd say you are incorrect
@wolf1728 is thinking about multiplicative inverses
I know
and I think you mean the inverse of a function
Yes I am freckles
evaluate both of those expressions above
if you get x you are right
if you don't get x, then it would be incorrect
I did: y = 5x + 6 x = 5y + 6 x - 6 = 5y (x - 6)/5 = y
your inverse is right and you can verify it by pluggin the inverse into the orginial and the orginial into the inverse as I did above and they should both evaluate to x
And the second option you gave is correct
Thanks for your help.
\[\text{ does } \frac{(5x+6)-6}{5} \text{ give you } x? \\ \text{ or } \\ 5(\frac{x-6}{5})+6 \text{ give you x} \\ \frac{(5x+6)-6}{5}=\frac{5x}{5}=x \\ 5(\frac{x-6}{5})+6=x-6+6=x\] the verification process proved you were right
Oh! So like f(g(x)) and g(f(x)) with the inverse function and the function.
yes
if f and g are inverses then f(g(x))=x and g(f(x))=x
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