A bar of metal is cooling from 1000°C to room temperature, 22°C. The temperature, H, of the bar t minutes after it starts cooling is given, in °C, by
H = 22 + 978^e(−0.1t.)

(a) Find the temperature of the bar at the end of one hour. (Round your answer to the nearest degree.)

Question

A bar of metal is cooling from 1000°C to room temperature, 22°C. The temperature, H, of the bar t minutes after it starts cooling is given, in °C, by
H = 22 + 978^e(−0.1t.)

(a) Find the temperature of the bar at the end of one hour. (Round your answer to the nearest degree.)

anonymous · Answer

b) Find the average value of the temperature over the first hour. (Round your answer to the nearest degree.)

jim_thompson5910 · Answer

part a) plug in t = 1 and evaluate to find H

part b) use the formula

$$\Large V=\frac{1}{b-a} \int_{a}^{b}(f(x))dx$$

to get the average temperature V. In this case, a = 0, b = 1

jim_thompson5910 · Answer

also, f(x) is the function 
$$\Large H(t) = 22 + 978e^{-0.1t}$$

anonymous · Answer

okay thank you!!!

jim_thompson5910 · Answer

np