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what lol do u want to help because u can :P
\[\sf \frac{x^3}{7^2} =7\]\[\sf x^3 = 7^{1+2}\] I cross multiplied the 7's. Reduce. \[\sf x^3 = 7^3\]Take the cube root of each side.\[\sf \sqrt[3]{x^3} =\sqrt[3]{343}\] simplify. \[\sf (x^3)^{1/3} = \sqrt[3]{343}\]\[\sf x = \sqrt[3]{343}\]
And reduce that, you'll find your answer for x.
x = 7?
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Yes :) Good job.
thank you!
do you mind helping with another its okay if not
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