Ask your own question, for FREE!
Physics 16 Online
OpenStudy (anonymous):

Tom has a mass of 70.0kg and Sally has a mass of 50kg. Tom and Sally are standing 20.0m apart on the dance floor. Sally looks up and sees tom. She feels an attraction . if the attraction is gravitational find it's size assume that both tom and Sally can be replaced by spherical masses

OpenStudy (michele_laino):

please you have to use the Newton's formula, namely: \[F=G \frac{ M _{T}*M _{S} }{ d ^{2} }\] where M_T is the mass of Tom, M_S, is the mass of Sally, d is the distance between them, and G is the gravitational constant, whose value is: \[6.673*10^{-11}\] S.I. units

OpenStudy (anonymous):

so what is the answers

OpenStudy (anonymous):

what is the answer

OpenStudy (michele_laino):

\[F=6.673*10^{-11}\frac{ 70*50 }{ 400 }=...\] please complete the calculus, it's very simple

OpenStudy (anonymous):

thanks you are so nice

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!