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Tom has a mass of 70.0kg and Sally has a mass of 50kg. Tom and Sally are standing 20.0m apart on the dance floor. Sally looks up and sees tom. She feels an attraction . if the attraction is gravitational find it's size assume that both tom and Sally can be replaced by spherical masses
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please you have to use the Newton's formula, namely: \[F=G \frac{ M _{T}*M _{S} }{ d ^{2} }\] where M_T is the mass of Tom, M_S, is the mass of Sally, d is the distance between them, and G is the gravitational constant, whose value is: \[6.673*10^{-11}\] S.I. units
so what is the answers
what is the answer
\[F=6.673*10^{-11}\frac{ 70*50 }{ 400 }=...\] please complete the calculus, it's very simple
thanks you are so nice
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