Question

Help with Algebra 2??

Answer 1

I think it's B

Answer 2

For any invertible 2x2 matrix A the inverse can be defined as \[A = \left[\begin{matrix} a & b \\ c & d \end{matrix}\right]\]\[A^{-1} = \frac{ 1 }{ \det A } \left[\begin{matrix} d & -b \\ -c & a\end{matrix}\right] = \frac{ 1 }{ ad-bc } \left[\begin{matrix} d & -b \\ -c & a\end{matrix}\right]\]

Answer 3

so the answer is A?

Answer 4

Yeah :)

Answer 5

thankyou!!

Answer 6

Yw!