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Can someone help me through this? http://prntscr.com/5asu2w @Jhannybean @Secret-Ninja @razor99 @geerky42 @bloopman
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Yeah sure, give me a second.
\[A = \frac{ 2b}{ 13}\]
\(\large\tt \begin{align} \color{black}{\dfrac{8}{15}=\dfrac{4a}{a+b}\\~\\ \dfrac{2}{15}=\dfrac{a}{a+b}\\~\\ \dfrac{15}{2}=\dfrac{a+b}{a}\\~\\ \dfrac{15}{2}-1=\dfrac{a+b}{a}-1\\~\\ \dfrac{15-2}{2}=\dfrac{a+b-a}{a}\\~\\ \dfrac{13}{2}=\dfrac{b}{a}\\~\\ \dfrac{2}{13}=\dfrac{a}{b}\\~\\ }\end{align}\)
So, could you answer from there?
\[\frac{8}{15}=\frac{4a}{a+b}\] euate the numerators and the denominators to eachother. \[8=4a\] solve for a\[15 = a+b\]
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so \[8 = 4a\]\[a=\frac{8}{4} = 2\]\[15 = 2 +b\]\[b=13\]
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