Question

help me with this????

Answer 1

For you to compare the difference between the two, you need to first get the volume of each cup.
Volume of a cone:
\[V = \frac{ 1 }{ 3 } \pi r^2 h\]
Volume of a cylinder:
\[V = \pi r^2 h\]

Answer 2

when i subtracted the 2 volumes i got 58.64

Answer 3

In the equations the volume is calculated by r, the radius of the cones and cylinder which would be half of the diameter, did you take that into account?

Answer 4

Volume of the cone cup:
\[V = \frac{ 1 }{ 3 } \pi (1)^2 (4)\]
\[V = \frac{ 4 }{ 3 } \pi \]
Volume of the cylinder cup:
\[V = \pi (1)^2 (6)\]
\[V = 6 \pi \]

Answer 5

14.7?

Answer 6

i guess you're right @Johnbc .. @piercetheveil47 did substitute 2in as r..

Answer 7

yep @piercetheveil47

Answer 8

thanks everyone!

Answer 9

@piercetheveil47 remember to take that into consideration.. the diameter-radius difference

Answer 10

Continuing the mathematics.
\[6 \pi = \frac{ 18 \pi }{ 3 }\]
\[V_2 - V_1 = \frac{ 18 \pi }{ 3 } - \frac{ 4 \pi }{ 3 } = \frac{ 14 \pi }{ 3} \]

And from just observing you can see that Pi is around 3.14 so the answer would be around 14.66