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OpenStudy (piercetheveil47):
OpenStudy (piercetheveil47):
@Johnbc
OpenStudy (kainui):
Have you heard about the Pythagorean Theorem?
OpenStudy (piercetheveil47):
yes hah
OpenStudy (piercetheveil47):
i got 85.8 when using the pythagorean theorem ( i did 56 and 65)
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OpenStudy (piercetheveil47):
??? like what do i do now??
OpenStudy (piercetheveil47):
@Kainui
OpenStudy (kainui):
How did you do 56 and 65?
OpenStudy (piercetheveil47):
i plugged it into the pythagorean theorem b/c it forms 2 sides of a triangle? right?
OpenStudy (piercetheveil47):
@Kainui
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OpenStudy (piercetheveil47):
@jim_thompson5910
OpenStudy (anonymous):
\[A^2 + B^2 = C^2\] Since you know you have one of the sides and the hypotenuse then you will have to solve for the other side
OpenStudy (kainui):
But you need to pay attention to what sides are what before you do it
OpenStudy (anonymous):
Lets say A is the side you are solving for then you will see that you will need to manipulate your formula to solve for that side you are looking for:
\[A = \sqrt{C^2 - B^2}\]
You may may have ran into an error because of the side you used in the formula.
OpenStudy (piercetheveil47):
ahhhh can someone give me an example using different numbers?
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OpenStudy (anonymous):
Since C corresponds to the hypotenuse you know you have to treat it as C in the Pythagorean Theorem:
\[A^2 + B^2 = C^2\]
OpenStudy (anonymous):
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OpenStudy (piercetheveil47):
ohhh okay :)
OpenStudy (anonymous):
If you like to work it out purely with numbers then you can begin with the formula and carry out the algebra for the missing variable, so for the example above:
\[A^2 + B^2 = C^2\]
\[(1)^2 + B^2 = (3)^2\]\[1 + B^2 = 9\]\[B^2 = 9 -1\]\[B^2 = 8\]\[B = \sqrt{8}\]