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Mathematics 7 Online
OpenStudy (piercetheveil47):

Help me??

OpenStudy (piercetheveil47):

OpenStudy (piercetheveil47):

@Johnbc

OpenStudy (kainui):

Have you heard about the Pythagorean Theorem?

OpenStudy (piercetheveil47):

yes hah

OpenStudy (piercetheveil47):

i got 85.8 when using the pythagorean theorem ( i did 56 and 65)

OpenStudy (piercetheveil47):

??? like what do i do now??

OpenStudy (piercetheveil47):

@Kainui

OpenStudy (kainui):

How did you do 56 and 65?

OpenStudy (piercetheveil47):

i plugged it into the pythagorean theorem b/c it forms 2 sides of a triangle? right?

OpenStudy (piercetheveil47):

@Kainui

OpenStudy (piercetheveil47):

@jim_thompson5910

OpenStudy (anonymous):

\[A^2 + B^2 = C^2\] Since you know you have one of the sides and the hypotenuse then you will have to solve for the other side

OpenStudy (kainui):

But you need to pay attention to what sides are what before you do it

OpenStudy (anonymous):

Lets say A is the side you are solving for then you will see that you will need to manipulate your formula to solve for that side you are looking for: \[A = \sqrt{C^2 - B^2}\] You may may have ran into an error because of the side you used in the formula.

OpenStudy (piercetheveil47):

ahhhh can someone give me an example using different numbers?

OpenStudy (anonymous):

Since C corresponds to the hypotenuse you know you have to treat it as C in the Pythagorean Theorem: \[A^2 + B^2 = C^2\]

OpenStudy (anonymous):

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OpenStudy (piercetheveil47):

ohhh okay :)

OpenStudy (anonymous):

If you like to work it out purely with numbers then you can begin with the formula and carry out the algebra for the missing variable, so for the example above: \[A^2 + B^2 = C^2\] \[(1)^2 + B^2 = (3)^2\]\[1 + B^2 = 9\]\[B^2 = 9 -1\]\[B^2 = 8\]\[B = \sqrt{8}\]

OpenStudy (piercetheveil47):

okay! thats easier to me !

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