Question

How many possibel values of k if equation kx^2-(k+2)x+k=0 and x^2-(k+1)x+k=0 has one same solution? Find the sum of the integer values of k.
PLEASE HELP IM IN 6TH GRADE IM INNOCENT AND SHOULDN'T BE DOING THESE PROBLEMS!!

Answer 1

Anyone? IF you answer and get it right i will fan you and give ou a medal

Answer 2

\[K=2x/x ^{2}-x+1\]

Answer 3

i need a value. answer the second quetion plz

Answer 4

i fanned both of u

Answer 5

how did u get what k equals? thx i think it is right

Answer 6

It's not. Try using the quadratic formula.

Answer 7

i did!

Answer 8

it didn't work, i didnt get the sum of the integer values of k

Answer 9

they have to have one ame answet

Answer 10

fanned Sithsandgiggles

Answer 11

fanned jonask

Answer 12

fanned anyone who saw my question

Answer 13

thx everyone i appreciate it

Answer 14

\(kx^2-(k+2)x+k=0\)

use the quadratic formular \[\dfrac{-b\pm sqrt{b^2-4ac}}{2a}\]
for first one
\[x=\frac{k+2\pm \sqrt{(k+2)^2-4k^2}}{2k}\]
\(x^2-(k+1)x+k=0\)
second one
\[x=\frac{k+1\pm \sqrt{(k+1)^2-4k}}{2}\]

you have to make this two solutions equal

Answer 15

gues that makes sense. but how do u make them equal? there are two variables and you can't must plug in variables. there could be millions of answers that would work.

Answer 16

i already tried that

Answer 17

notice that there are two solutions from each of those,and you have four equations,you will decide wich pairs are equal

Answer 18

if they are not equal ,you will get no solution for the equality

Answer 19

four equations, so how do u know which 2 are equal?

Answer 20

there is a solution, i just dont know what it is. I have to find the sum of all the values of k

Answer 21

the easy way is to think like this:for equations to have same roots,the need to satisfy the following conditions

Sum of roots=\(\dfrac{-b}{a}\)

product of roots =\(\dfrac{c}{a}\)

Answer 22

ya, thats the vieta theroem. but how does that help me?

Answer 23

you could use the LHS from the first solution and RHS from the second equation

Answer 24

whats a lhs and a rhs

Answer 25

from first equation \[x_1+x_2=\frac{k+2+ \sqrt{(k+2)^2-4k^2}}{2k}+\frac{k+2- \sqrt{(k+2)^2-4k^2}}{2k}=\dfrac{k+2}{k}\]

\[=-\frac{b}{a}_{from \space 2nd \space equation}=\frac{k+1}{2}\]

Answer 26

LHS=left hand side
RHS =Right hand side

Answer 27

ohhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Answer 28

omg i get it now thx

Answer 29

i'm glad you do,you show understanding i wish you'll be able to solve it

Answer 30

\[\frac{k+2}{k}=\frac{k+1}{2}\]