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Detremine the root mean square speed of CO2 molecules that have an average kenetic energy of 4.21 X 10^-21
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kinetic energy=1/2mv^2
m is the molar mass, and v is the speed.
First step: Find the molar mass of CO2
Then you just substitute & simplify :)
this is what I got when I worked it out but its saying its wrong. 9.26399975 X 10^-20
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What did you do exactly?
\(\Large v_{rms}=\sqrt{\dfrac{2KE}{m_{CO_2}}}\) m= mass of onle molecule
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