Question

Can someone please help me with this problem
x^2= 17/5x+12/5

Answer 1

multiply every term by 5x... removes the denominators

\[5x^3 = 17 + 12x\]

or

\[5x^3 - 12x - 17 = 0\]

Answer 2

Wouldn't you just have to multiply everything by 5 and you would get \[5x^2-17x-12=0\]

Answer 3

ok... so the term 12/5x is really

\[\frac{12}{5} x ~~~ I ~~thought ~~ \it~~ was ~~~\frac{12}{5x}\]

so yes you are correct...

Answer 4

if yours is correct you can solve by gruoping in pairs

\[5x^2 + 5x - 17x - 17 = 0\]

hope it helps