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Calculus1 17 Online
OpenStudy (anonymous):

Why can there be no relative extrema in a closed interval?

OpenStudy (anonymous):

I really appreciate any help to understand this, because I really can't get why there can be no relative extrema at the endpoints |: For instance, within the closed interval [2.40, 4.72] of the function \(f(x) = sin(x) + cos(4x)\), the relative extrema lie at the endpoints, while the absolute extrema lie somewhere in between: http://s14.postimg.org/v6aeq2vup/Relative_Min_Max.jpg If the reason is because I can't know for sure whether the function is differentiable coming from the side left out of the interval (to say, coming from the right toward the rightmost endpoint), then how can a function like the of the image below have a relative maximum at x = -2, when the derivative at that point doesn't exist? http://s30.postimg.org/pt0h2q61t/Relative_Min_Max2.jpg I know that there can be a critical point when f' = 0 or undefined, but I'm trying to point out that having relative extrema only in open intervals seems a somewhat arbitrary definition, not linked with any of the thing about critical points I've learned so far ): Thanks !!

OpenStudy (anonymous):

@uri

OpenStudy (anonymous):

Sure there can be relative extrema in a closed interval. But it does not make sense to talk about relative extrema at the endpoints because you don't know what happens outside of the interval. For example, x and |x| look the same on [0, 1] but only one of them has a relative extremum at the origin. If you only know what happens on [0, 1] you can't tell them apart. We need to restrict ourselves to avoid ambiguity.

OpenStudy (loser66):

Relative extrema and absolute extrema are the concepts indicate to the high points and highest points in the interval. What makes you think absolute extrema must bound relative one?

OpenStudy (loser66):

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