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Chemistry 13 Online
OpenStudy (sleepyjess):

When the following equation is balanced with the lowest whole number coefficients possible, what is the coefficient in front of HNO3? \(N_2O_5 + H_2O \rightarrow HNO_3\) 1 \(\leftarrow\) 2 4 5

OpenStudy (sleepyjess):

@abb0t

OpenStudy (sleepyjess):

@nincompoop @Abhisar

OpenStudy (sleepyjess):

@ganeshie8

OpenStudy (abhisar):

Have you tried to balance the equation first?

OpenStudy (sleepyjess):

\(2HN_2O_6\)?

OpenStudy (abhisar):

\(\sf HN_2O_6\) ?

OpenStudy (sleepyjess):

Wouldn't there be 2H though?

OpenStudy (abhisar):

You have to balance \(\sf N2O5+H2O→HNO3\)

OpenStudy (abhisar):

The correct balanced equation will be \(\sf N_2O_5 + H_2O = 2 HNO_3\) Can u find the correct option now?

OpenStudy (sleepyjess):

2

OpenStudy (abhisar):

\(\huge \checkmark\)

OpenStudy (sleepyjess):

Wow I didn't know you could do check marks!

OpenStudy (abhisar):

:D use `\(\hhuge \checkmark\)`

OpenStudy (abhisar):

Sorry It's `\(\huge \checkmark\)`

OpenStudy (sleepyjess):

\(\huge \checkmark\)

OpenStudy (sleepyjess):

\(\Huge\cal\color{blue}{\ddot\smile ~Thanks!}\)

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