Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

@Michele_Laino

OpenStudy (anonymous):

it is none of the above right?

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

please you have to apply the subsequent rule: \[\frac{ d (x ^{n}) }{ dx }=n*x ^{(n-1)}, n \in \mathbb{N} \] nevertheless n can be any real number

OpenStudy (michele_laino):

for example: \[\frac{ dx ^{3} }{ dx }=3x ^{2}\] so \[\frac{ d4x ^{3} }{ dx }=12x^{2}\] that's the first term of your answer, please continue that calculus

OpenStudy (michele_laino):

for example the derivative of the second term is: \[\frac{ d(-3x ^{2}) }{ dx }=-6x\] now, try to calculate the derivative of the third term of your polynomial, please

OpenStudy (anonymous):

9 @Michele_Laino

OpenStudy (anonymous):

12x^2-6x+9 right?

OpenStudy (anonymous):

which would be none of the above(:

OpenStudy (michele_laino):

perfect! your answer is right, namely noone of the answers listed

OpenStudy (michele_laino):

I'm ready!

OpenStudy (anonymous):

iis it -24 in^2/hour?

OpenStudy (michele_laino):

the rate of 1.5 inches/hour is referring to an edge of your cube?

OpenStudy (anonymous):

noo how fast its melting

OpenStudy (michele_laino):

I think the formulae are these: \[\frac{ dl }{ dt }=-1.5\] so we can write: \[l(t)=-1.5*t+l _{0}\] where l_0 is the initial length furthermore, we have: \[A(t)=[l(t)]^{2}\] so: \[\frac{ dA }{ dt }=2*l(t)*\frac{ dl }{ dt }=2*(-1.5t+l _{0})*(-1.5)\]

OpenStudy (michele_laino):

do you know what is the initial length of your cube?

OpenStudy (anonymous):

side length of 2 inches?

OpenStudy (michele_laino):

I think that it must be greater than 2 inches

OpenStudy (michele_laino):

don't worry I got the solution: in order to find our rate you havet calculate this \[\frac{ dS }{ dt }=2*2*(-1.5)=-6\] we don't needto know what is the initial lenftg of a sidof ur cube, because at the time when the side of o cube has a lenfgth equalss to 2, we can write: l_0-1.5t=2, without need to know what is l_0

OpenStudy (michele_laino):

@mondona

OpenStudy (anonymous):

and then what do we do?

OpenStudy (michele_laino):

rate of changing (decreasing) area is 6 inches^2/hour

OpenStudy (anonymous):

so it would be negative right?

OpenStudy (michele_laino):

that's right, because during melting the dimensions of our ice cube are decreasing, so also area does that

OpenStudy (anonymous):

6 wouldnt be right..

OpenStudy (michele_laino):

I think that your problem calls surface the total surface of our cube, whereas my calculus is refferring to the surface of only one face of the cube. So in order to get the right answer, you have to multiply -6 by 6, and you will get: \[\frac{ dS }{ dt }=6*(-6)=-36\] inches/hour since, of course a cube has six faces

OpenStudy (michele_laino):

so the third option is the right answer!

OpenStudy (anonymous):

ohhh thats what i thought i was thinking about that

OpenStudy (anonymous):

thank you !

OpenStudy (michele_laino):

thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!