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What are the zeros and their multiplicities of the function f(x)=x^4-4x^3+3x^2?
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please, start putting in evidence the common factor x^2, write yur answer
How is the common factor x^2?
well x^2 will divide exactly into all 3 terms of the function
\[ f(x)=x^4-4x^3+3x^2=x^2(x^2-4x+3)\]
evidently \(0\) is a zero with multiplicity \(2\) as you have one factor of \(x^2\)
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the other zeros you can find by either factoring \(x^2-4x+3\) or using the quadratic formula
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