What are the roots of the quadratic equation xÆ – 2x + 4 = 8x – 21?
do you know how to factor a quadratic?
No
ok... so.. .what instructions are you meant to use to get the factors?
im sorry i dont understand ..
well.. you're expected to find the roots, or zeros what instructions are you meant to use to find the roots ? there are several ways... but dunno what the exercise is covering
I mean i honestly dont know. Im taking an online math class and its not really teaching me anything. It just gives me problems like these and thats it .
hmmm well... sounds like they're not help then you're meant to have covered that section before doing the exercises otherwise..... I mean.. .what if decide to give you an exercise on say physics in initial velocity, if you dunno what that is.or haven't covered it.. the exercise wouldn't apply
Yea there really not. And its awful because i need this class to graduate. Its awful and its hard. Thats why im on this website to get help
well.... do you know how to do linear simplification? like say, solving for a variable
yes
ok ... then let's see yours \(\bf x^2 - 2x + 4 = 8x - 21\) if you moved everything to the left-hand-side.... what would you be left with?
bearing in mind that the "x" and constant terms, simplify themselves
x^2-2x-8x+4-21=0 .. ?
Is there anyway you can help me with my other assignments ?
well \(\large { x^2 - 2x + 4 = 8x - 21\implies x^2-2x+4-8x+21=0 \\ \quad \\ x^2-10x+25=0\qquad notice\implies \begin{array}{cccllll} x^2&-10x&+25&=0\\ &\uparrow &\uparrow \\ &-5-5&-5\cdot -5 \end{array} }\) notice that, the middle term can come from ADDING 2 factors, of the last term "25" and that the same factors can be used to produce the last term, or "25"
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