Question

Find an equation of the line containing the given pair of points.
(1/4, -1/2)and (3/4, 6) Type your answer in slope intercept form.

Answer 1

First find the slope(m) by using y2-y1/x2-x1
then for the equation use this formula y-y1=m(x-x1)

Answer 2

ok

Answer 3

6.5/0.5 is the slope but does this reduce

Answer 4

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ \frac{1}{4}}}\quad ,&{\color{blue}{ -\frac{1}{2}}})\quad &({\color{red}{ \frac{3}{4}}}\quad ,&{\color{blue}{ 6}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 5

ok

Answer 6

1/4=x1 and 3/4=x2
-1/2=y1 and 6=y2

Answer 7

ok

Answer 8

hmm lemme fix that a bit

Answer 9

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ \frac{1}{4}}}\quad ,&{\color{blue}{ -\frac{1}{2}}})\quad &({\color{red}{ \frac{3}{4}}}\quad ,&{\color{blue}{ 6}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{6}}-{\color{blue}{ \left(-\frac{1}{2}\right)}}}{{\color{red}{ \frac{3}{4}}}-{\color{red}{ \frac{1}{4}}}}\implies \cfrac{6+\frac{1}{2}}{\frac{3}{4}-\frac{1}{4}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form} \)

Answer 10

har har saw that :P

is actually red :) but orange sounds tastier