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Mathematics 14 Online
OpenStudy (blackstreet23):

How can I verify this identity? Sin 2t - tan t = tan t cos 2t

OpenStudy (perl):

you can start from the left side

OpenStudy (perl):

sin(2t) - tan(t) = 2 sin(t) cos(t) - tan(t) = 2 sin (t) cos(t) - sin(t) / cos(t)

OpenStudy (blackstreet23):

And then?

OpenStudy (perl):

then make a common denominator

OpenStudy (perl):

sin(2t) - tan(t) = 2 sin(t) cos(t) - tan(t) = 2 sin (t) cos(t) - sin(t) / cos(t) = 2 sin (t) cos(t)*[cos(t)/ cos(t)] - sin(t) / cos(t) = [2 sin (t) cos^2(t) - sin(t)] / cos(t) = sin(t) ( 2cos^2(t) -1 ) / cos(t)

OpenStudy (perl):

now you are very close to the conclusion

OpenStudy (jdoe0001):

<rolling drums> <growing suspense> <sweaty palms> so.... what do you have thus far?

OpenStudy (perl):

hint: use substitition cos(2t) = 2cos^2(t) - 1

OpenStudy (blackstreet23):

I am still stuck in (2 sin t cost t) - (sin / cos)

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