The net profit of a company for the years 2000 to 2011 is approximated by the function p(t) = t³ – 5tÆ + 6t, where p is the profit (in thousands of dollars) and t is the number of years that have passed since January 1, 2000. For which period will the company report a net loss?
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jimthompson5910 (jim_thompson5910):
type in x^3 - 5x^2 + 6x into the calculator
OpenStudy (anonymous):
okay
jimthompson5910 (jim_thompson5910):
when is the curve below the x axis? for which x values?
keep in mind that x >= 0
OpenStudy (anonymous):
its below the x-axis between the positive 2 and 3
jimthompson5910 (jim_thompson5910):
correct
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jimthompson5910 (jim_thompson5910):
x corresponds to the number of years after the year 2000
jimthompson5910 (jim_thompson5910):
since 2 < x < 3 is when p(t) is below the x axis, this means
the company has a net loss between 2002 and 2003
OpenStudy (anonymous):
so the answer is ' January 1,2002-December 31,2002 ?
jimthompson5910 (jim_thompson5910):
well on Jan 1, 2002, the p(t) value is actually 0
this is because p(2) = 0. There is no net profit and no net loss
the next day is when the losses start happening and they continue to happen until Jan 1, 2003. On this day, you break even again because p(3) = 0. Everything after t = 3 is a net profit
jimthompson5910 (jim_thompson5910):
So I'd say from Jan 2, 2002 to Dec 31, 2002 is when you'd have a net loss
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OpenStudy (anonymous):
Thank you soooo much : ) I have one more question
jimthompson5910 (jim_thompson5910):
alright
OpenStudy (anonymous):
Which statement about the graph of the rational expression
x^2+6x+9 / x^2-4
jimthompson5910 (jim_thompson5910):
seems like an incomplete question
OpenStudy (anonymous):
function is above the x axis between -2 and 2.
function is above the x axis and x is greater than 2.
function is below the x axis for x is less than -2.
function is below x axis between -3 and -2
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OpenStudy (anonymous):
Do I use the graphing calculator?
jimthompson5910 (jim_thompson5910):
so graph (x^2+6x+9)/(x^2-4) using desmos and you should see the answer (or at least eliminate the nonanswers)
jimthompson5910 (jim_thompson5910):
yes you would
OpenStudy (anonymous):
How do I divide using the graphing calculator? I'm using the / symbol but it's making the 9 the numerator instead of dividing the whole equation
jimthompson5910 (jim_thompson5910):
you need to put parenthesis around the whole numerator
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jimthompson5910 (jim_thompson5910):
same with the denominator
jimthompson5910 (jim_thompson5910):
(numerator)/(denominator)
jimthompson5910 (jim_thompson5910):
which is why you type in (x^2+6x+9)/(x^2-4)
OpenStudy (anonymous):
ok I used the ( )
jimthompson5910 (jim_thompson5910):
so what answers do you see? or what answers can you eliminate?
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OpenStudy (anonymous):
We can eliminate anything below the x axis?
jimthompson5910 (jim_thompson5910):
lets go through the answer choices
jimthompson5910 (jim_thompson5910):
"function is above the x axis between -2 and 2"
is that true or false?
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
false
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jimthompson5910 (jim_thompson5910):
why is it false
jimthompson5910 (jim_thompson5910):
which parts aren't above the x axis?
OpenStudy (anonymous):
I'm looking at it again. One moment
OpenStudy (anonymous):
Honestly, I'm not sure exactly what I'm looking at. Is it quadrant 3?
jimthompson5910 (jim_thompson5910):
well notice between x = -2 and x = 2 the entire portion of the graph is below the x axis
not above
so that's why A is false
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OpenStudy (anonymous):
OK, that makes sense. Let me look at b.
jimthompson5910 (jim_thompson5910):
I'm assuming B is supposed to say "function is above the x axis when x is greater than 2."
instead of "function is above the x axis and x is greater than 2."
OpenStudy (anonymous):
b would be true
jimthompson5910 (jim_thompson5910):
yes it is, when x > 2, the curve is above the x axis
jimthompson5910 (jim_thompson5910):
choice C
"function is below the x axis for x is less than -2."
true or false?
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OpenStudy (anonymous):
true
jimthompson5910 (jim_thompson5910):
why true?
jimthompson5910 (jim_thompson5910):
is the curve below the x axis when you are to the left of x = -2 ?
OpenStudy (anonymous):
No it isn't. That's false.
jimthompson5910 (jim_thompson5910):
correct
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jimthompson5910 (jim_thompson5910):
finally choice D
"function is below x axis between -3 and -2"
true or false?
OpenStudy (anonymous):
false
OpenStudy (anonymous):
so the answer is b
jimthompson5910 (jim_thompson5910):
yes because the portion between x = -3 and x = -2 is above
jimthompson5910 (jim_thompson5910):
yes it is B
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