Question

What would be the resulting chromosomal # in each resulting gamete if non disjunction of two chromosomes occured in Meiosis 1 ?

Answer 1

Nondisjunction events during meiosis I are of special importance since most clinically relevant aneuploidies in humans result from this type of segregation error.[5] At the beginning of meiosis I, pairs of homologous chromosomes, also known as bivalents, assemble following homologous recombination. Failure of segregation of a bivalent in anaphase I goes by three separate names: "MI", "homologue" or "classic" nondisjunction.[5]

Answer 2

u there

Answer 3

Hi yes sorry for the late reply

Answer 4

okay did u find my answer help ful

Answer 5

Well I was told to draw out the resulting gamates, wasnt too sure how to do that

Answer 6

Draw out the steps

Answer 7

Nondisjunction in meiosis I
Trisomy is most frequently caused by nondisjunction in maternal meiosis I. The sequence of events of this type of nondisjunction is schematically contrasted with normal meiosis. In metaphase I, the two homologous chromosomes assemble in the so-called bivalent, which enables inter-chromosomal exchange of genetic material through homologous recombination. Failure of separating the bivalent properly in meiosis I may result in retention of both homologous chromosomes in the oocyte. After fertilization, this results in trisomy of the respective chromosome. (The other alternative of nondisjunction in meiosis I, not shown here, involves extrusion of both homologous chromosomes into the polar body I, which after fertilization leads to monosomy.)
Nondisjunction events during meiosis I are of special importance since mos

Answer 8

see the attachment