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\[\sum_{n=1}^{\infty}\frac{ 1 }{ \sum_{n=1}^{\infty} k^3}\]
the index in denominator is \(k\) right ?
\[\sum_{n=1}^{\infty}\frac{ 1 }{ \sum_{\color{red}{k}=1}^{\infty} k^3}\]
YUP SRY
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